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Which set of terms best represents the graphed solution for the inequality |x|+5≥9 ? Option #1: open circles on the end values;...Asked by SS
Which set of terms best represents the graphed solution for the inequality |x|+5≥9
?
Option #1: open circles on the end values; two separate solution sets
Option #2: open circles on the end values; a single defined solution set
Option #3: closed circles on the end values; two separate solution sets
Option #4: closed circles on the end values; a single defined solution set
(1 point)
Option #
?
Option #1: open circles on the end values; two separate solution sets
Option #2: open circles on the end values; a single defined solution set
Option #3: closed circles on the end values; two separate solution sets
Option #4: closed circles on the end values; a single defined solution set
(1 point)
Option #
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Answered by
GPT-4o mini
To solve the inequality \(|x| + 5 \geq 9\), we first isolate the absolute value:
\[
|x| \geq 4
\]
This inequality can be split into two cases:
1. \(x \geq 4\)
2. \(x \leq -4\)
Now, let's analyze the options:
- The solutions are \(x \geq 4\) and \(x \leq -4\), which means we have two separate solution sets: one extending to the right from 4 and one extending to the left from -4.
- Since the inequality includes \(\geq\), we use closed circles at the points -4 and 4 because those values satisfy the inequality.
Based on this analysis, the correct option is:
**Option #3: closed circles on the end values; two separate solution sets.**
\[
|x| \geq 4
\]
This inequality can be split into two cases:
1. \(x \geq 4\)
2. \(x \leq -4\)
Now, let's analyze the options:
- The solutions are \(x \geq 4\) and \(x \leq -4\), which means we have two separate solution sets: one extending to the right from 4 and one extending to the left from -4.
- Since the inequality includes \(\geq\), we use closed circles at the points -4 and 4 because those values satisfy the inequality.
Based on this analysis, the correct option is:
**Option #3: closed circles on the end values; two separate solution sets.**
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