To order the given rational numbers from least to greatest, we will first convert all of them to improper fractions for easier comparison:
- Negative 1: This is \(-1 = -\frac{1}{1}\).
- Negative 1 and one-half: This is \(-1.5 = -\frac{3}{2}\).
- Negative 1 and one-fourth: This is \(-1.25 = -\frac{5}{4}\).
- Negative 1 and \(\frac{7}{8}\): This is \(-1.875 = -\frac{15}{8}\).
Now we have the following numbers as improper fractions:
- \(-1\) is \(-\frac{1}{1}\) or \(-\frac{8}{8}\)
- \(-1 \frac{1}{2}\) is \(-\frac{3}{2}\)
- \(-1 \frac{1}{4}\) is \(-\frac{5}{4}\)
- \(-1 \frac{7}{8}\) is \(-\frac{15}{8}\)
Next, we will compare and place these fractions on a number line:
- \(-\frac{15}{8} \approx -1.875\) (Least)
- \(-\frac{3}{2} = -1.5\)
- \(-\frac{5}{4} = -1.25\)
- \(-\frac{8}{8} = -1\) (Greatest)
Now we can order them from least to greatest:
- \(-1 \frac{7}{8}\)
- \(-1 \frac{1}{2}\)
- \(-1 \frac{1}{4}\)
- \(-1\)
So, the correct order from least to greatest is:
Negative 1 and \(\frac{7}{8}\), negative 1 and one-half, negative 1 and one-fourth, negative 1.
Thus, the answer is:
Negative 1 and \(\frac{7}{8}\), negative 1 and one-half, negative 1 and one-fourth, negative 1.