Which sentence below includes a compound verb?
(1 point)
Responses
The wolf pounced on a mouse and ate it.
The wolf pounced on a mouse and ate it.
The wolf’s underfur grew dense and thick.
The wolf’s underfur grew dense and thick.
Hares and caribou are among the wolf’s prey.
9 answers
The wolf pounced on a mouse and ate it.
Solve for p.
3(p + q) = p
(1 point)
Responses
q = –two-thirdsp
q = – Image with alt text: two-thirds p
q = –start fraction three over two end fractionp
q = – Image with alt text: start fraction three over two end fraction p
p = –two-thirdsq
p = – Image with alt text: two-thirds q
p = –start fraction three over two end fractionq
3(p + q) = p
(1 point)
Responses
q = –two-thirdsp
q = – Image with alt text: two-thirds p
q = –start fraction three over two end fractionp
q = – Image with alt text: start fraction three over two end fraction p
p = –two-thirdsq
p = – Image with alt text: two-thirds q
p = –start fraction three over two end fractionq
p = –start fraction three over two end fractionq
Solve for b, then find the value of b when a = 3.
4a = 2b − 7
(1 point)
Responses
–nine-halves
– Image with alt text: nine-halves
five-halves
Image with alt text: five-halves
nineteen-halves
Image with alt text: nineteen-halves
17
4a = 2b − 7
(1 point)
Responses
–nine-halves
– Image with alt text: nine-halves
five-halves
Image with alt text: five-halves
nineteen-halves
Image with alt text: nineteen-halves
17
To solve for b, we need to isolate b in the equation 4a = 2b - 7.
4a + 7 = 2b
Divide both sides by 2:
(4a + 7)/2 = b
2a + 7/2 = b
Now we can substitute a = 3 into the equation to find the value of b:
2(3) + 7/2 = b
6 + 7/2 = b
12/2 + 7/2 = b
19/2 = b
The value of b when a = 3 is nineteen-halves.
4a + 7 = 2b
Divide both sides by 2:
(4a + 7)/2 = b
2a + 7/2 = b
Now we can substitute a = 3 into the equation to find the value of b:
2(3) + 7/2 = b
6 + 7/2 = b
12/2 + 7/2 = b
19/2 = b
The value of b when a = 3 is nineteen-halves.
Solve for r.
d = rt
(1 point)
Responses
r = dt
r = dt
r equals t over d
Image with alt text: r equals t over d
r equals d over t
Image with alt text: r equals d over t
r equals d minus t
d = rt
(1 point)
Responses
r = dt
r = dt
r equals t over d
Image with alt text: r equals t over d
r equals d over t
Image with alt text: r equals d over t
r equals d minus t
r = d over t
Find the width of a rectangle with a perimeter of 90 and a length of 15.
(1 point)
Responses
90
90
15
15
45
45
30
(1 point)
Responses
90
90
15
15
45
45
30
To find the width of the rectangle, we need to use the formula for the perimeter of a rectangle, which is P = 2l + 2w, where P is the perimeter, l is the length, and w is the width.
Given that the length is 15 and the perimeter is 90, we can substitute these values into the formula:
90 = 2(15) + 2w
90 = 30 + 2w
60 = 2w
w = 60/2
w = 30
Therefore, the width of the rectangle is 30.
Given that the length is 15 and the perimeter is 90, we can substitute these values into the formula:
90 = 2(15) + 2w
90 = 30 + 2w
60 = 2w
w = 60/2
w = 30
Therefore, the width of the rectangle is 30.
1 answer