To determine which scenario best describes the graph with a y-intercept of $30, we need to analyze the different scenarios provided based on the initial amount of savings and how much the savings increase each week.
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Juan starts with $30 in savings and increases his savings amount by $5 each week.
- Initial savings: $30
- Weekly increase: $5
- Equation: \( y = 30 + 5x \)
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Juan starts with $30 in savings and increases his savings amount by $1 each week.
- Initial savings: $30
- Weekly increase: $1
- Equation: \( y = 30 + 1x \)
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Juan starts with $5 in savings and increases his savings amount by $30 each week.
- Initial savings: $5
- Weekly increase: $30
- Equation: \( y = 5 + 30x \)
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Juan starts with $5 in savings and increases his savings amount by $30 each week.
- Initial savings: $5
- Weekly increase: $30
- Equation: \( y = 5 + 30x \)
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Juan saves $30 per week.
- Assuming he starts with $0, the equation would be \( y = 30x \).
From the scenarios, the first two have a y-intercept of $30, meaning both begin from $30 in savings. The crucial difference is their week-to-week increase, which affects the slope of the line in the graph.
However, since the question states that the y-intercept is $30 and doesn't specify the weekly increase as a factor in determining the correct graph, either of the first two scenarios can accurately represent the graph with a $30 starting amount.
In conclusion, either of the first two scenarios is correct regarding the y-intercept of $30:
- Juan starts with $30 in savings and increases his savings amount by $5 each week.
- Juan starts with $30 in savings and increases his savings amount by $1 each week.
If you need to choose just one scenario with a stronger emphasis on savings being incremented regularly, the first option might be the most intuitive as it suggests a higher increase over time.