To solve \( 525 \div 25 \) using the method of partial quotients, we want to break down the division into simpler steps.
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Divide the numbers: We want to see how many times 25 can fit into 525. We can start with some easy multiples of 25.
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Find multiples of 25:
- Starting with 25, we find:
- \( 25 \times 10 = 250 \)
- \( 25 \times 20 = 500 \)
- \( 25 \times 21 = 525 \)
- Starting with 25, we find:
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Subtract and continue:
- First, we can take \( 25 \times 20 = 500 \).
- Subtract that from 525: \[ 525 - 500 = 25 \]
- Now we see how many times 25 fits into the remainder: \[ 25 \div 25 = 1 \]
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Combine partial quotients:
- From Step 2, we found that \( 25 \) fits into \( 525 \) \( 20 \) times, and we found one more time in the remaining \( 25 \).
- Thus, the total is: \[ 20 + 1 = 21 \]
So the complete quotient of \( 525 \div 25 \) using the method of partial quotients is 21.