To determine which quotient is between -4 and -5, we need to calculate each of the provided options.
-
\( 1 \frac{2}{3} \div (-\frac{1}{2}) \)
- Convert \( 1 \frac{2}{3} \) to an improper fraction: \[ 1 \frac{2}{3} = \frac{5}{3} \]
- Perform the division: \[ \frac{5}{3} \div (-\frac{1}{2}) = \frac{5}{3} \times (-2) = -\frac{10}{3} \approx -3.33 \]
-
\( -5 \frac{1}{2} \div (-1 \frac{1}{2}) \)
- Convert both to improper fractions: \[ -5 \frac{1}{2} = -\frac{11}{2}, \quad -1 \frac{1}{2} = -\frac{3}{2} \]
- Perform the division: \[ -\frac{11}{2} \div -\frac{3}{2} = \frac{11}{2} \times \frac{2}{3} = \frac{11}{3} \approx 3.67 \]
-
\( 2 \frac{5}{6} \div (-\frac{1}{2}) \)
- Convert \( 2 \frac{5}{6} \) to an improper fraction: \[ 2 \frac{5}{6} = \frac{17}{6} \]
- Perform the division: \[ \frac{17}{6} \div (-\frac{1}{2}) = \frac{17}{6} \times (-2) = -\frac{34}{6} = -\frac{17}{3} \approx -5.67 \]
-
\( -9 \frac{1}{3} \div 2 \)
- Convert \( -9 \frac{1}{3} \) to an improper fraction: \[ -9 \frac{1}{3} = -\frac{28}{3} \]
- Perform the division: \[ -\frac{28}{3} \div 2 = -\frac{28}{3} \times \frac{1}{2} = -\frac{28}{6} = -\frac{14}{3} \approx -4.67 \]
Now, let's summarize the results:
- \( \approx -3.33 \)
- \( \approx 3.67 \)
- \( \approx -5.67 \) (not between -4 and -5)
- \( \approx -4.67 \) (between -4 and -5)
The answer is \( -9 \frac{1}{3} \div 2 \), which is approximately -4.67 and falls between -4 and -5.