2 x + 2 y = 8
2 x - 1 y = 2
------------- subtract
0 x + 3 y = 6
y = 2
so
x = 2
x and y are both positive, first quadrant, upper right
Which quadrant does the solution of the system fail?
x+y=4
2x-y=2
Please help I don't know what to do. I don't what the answer, just want to be guided to it! Thank you (:
3 answers
Thank you so much.. It means a lot!!!!!!! :D
Is this even right