your given system can be written in the following matrix form
[ 5-4]*[x]=[-2]
[-2 3] [y] [6]
the inverse of the first matrix is
1/17 of
[ 5-4]
[-2 3]
if you multiply the left side by that inverse you get the identity matrix
[1 0]
[0 1]
of course you would then also multiply the right side by that , so it looks like the last answer is the correct one
which product represents the solution to the system 3x+4y=-2 and 2x+5y=6
[3 2]*[-2
[4 5] [6]
1/7[3 2]*[-2]
[4 5] [6]
[5 -2]*[-2]
[-4 3] [6]
1/7[5 -4]*[-2]
[-2 3] [6]
could someone explain
2 answers
oops!!
that first matrix of course should have been
[ 3 4]*[x]=[-2]
[ 2 5] [y] [6]
I copied incorrectly from my paper
that first matrix of course should have been
[ 3 4]*[x]=[-2]
[ 2 5] [y] [6]
I copied incorrectly from my paper