Which point on the axis satisfies the inequality y < x? (1 point)
(0, 1) (–1, 0) (1, 0) (0, 0)
7 answers
The point that satisfies the inequality y < x is (-1, 0).
In the graph of the inequality x – 2y ≥ 4, which is a value for x on the boundary line and the x-axis?
(1 point)
4 –2 2 –4
(1 point)
4 –2 2 –4
To find a value for x on the boundary line and the x-axis, we set y = 0 and solve for x in the inequality x - 2y ≥ 4.
Substituting y = 0, we get x - 2(0) ≥ 4, which simplifies to x ≥ 4.
Therefore, a value for x on the boundary line and the x-axis is 4.
Substituting y = 0, we get x - 2(0) ≥ 4, which simplifies to x ≥ 4.
Therefore, a value for x on the boundary line and the x-axis is 4.
If x ≥ 0 and y ≥ 0, then which quadrant holds the solution? (1 point)
IV III I II
IV III I II
If x ≥ 0 and y ≥ 0, it means that both x and y are non-negative. In the coordinate plane, the first quadrant (I) is where both x and y are positive. Therefore, since x and y are non-negative, the solution lies in the first quadrant (I).
Which ordered pair is a solution of the inequality? y ≥ 4x – 5
(1 point)
(3, 4) (2, 1) (3, 0) (1, 1)
(1 point)
(3, 4) (2, 1) (3, 0) (1, 1)
To determine which ordered pair is a solution of the inequality y ≥ 4x - 5, we substitute the x and y-values of each ordered pair into the inequality and see which one satisfies the inequality.
By substituting the values from each ordered pair, we get:
For (3, 4): 4 ≥ 4(3) - 5
4 ≥ 12 - 5
4 ≥ 7
This is not true, so (3, 4) is not a solution.
For (2, 1): 1 ≥ 4(2) - 5
1 ≥ 8 - 5
1 ≥ 3
This is not true, so (2,1) is not a solution.
For (3, 0): 0 ≥ 4(3) - 5
0 ≥ 12 - 5
0 ≥ 7
This is not true, so (3, 0) is not a solution.
For (1,1): 1 ≥ 4(1) - 5
1 ≥ 4 - 5
1 ≥ -1
This is true, so (1, 1) is a solution.
Therefore, the ordered pair (1, 1) is a solution of the inequality y ≥ 4x - 5.
By substituting the values from each ordered pair, we get:
For (3, 4): 4 ≥ 4(3) - 5
4 ≥ 12 - 5
4 ≥ 7
This is not true, so (3, 4) is not a solution.
For (2, 1): 1 ≥ 4(2) - 5
1 ≥ 8 - 5
1 ≥ 3
This is not true, so (2,1) is not a solution.
For (3, 0): 0 ≥ 4(3) - 5
0 ≥ 12 - 5
0 ≥ 7
This is not true, so (3, 0) is not a solution.
For (1,1): 1 ≥ 4(1) - 5
1 ≥ 4 - 5
1 ≥ -1
This is true, so (1, 1) is a solution.
Therefore, the ordered pair (1, 1) is a solution of the inequality y ≥ 4x - 5.