Which point has a distance of 5 from the point (0, -1)? * 1 point (5, 3) (-5, -1) (-1, 6) (0, 4)

Answer 1

To find the point(s) that have a distance of 5 from the point (0, -1), we can use the distance formula.

The distance formula is given by:

d = √((x2 - x1)² + (y2 - y1)²)

Substituting the values of (0, -1) for (x1, y1) and the values of (x, y) from the given points, we can calculate the distance from each point to (0, -1).

For point (5, 3):
d = √((5 - 0)² + (3 - (-1))²) = √(25 + 16) = √41 ≈ 6.4 (not 5)

For point (-5, -1):
d = √((-5 - 0)² + (-1 - (-1))²) = √(25 + 0) = 5

For point (-1, 6):
d = √((-1 - 0)² + (6 - (-1))²) = √(1 + 49) = √50 ≈ 7.1 (not 5)

For point (0, 4):
d = √((0 - 0)² + (4 - (-1))²) = √(0 + 25) = √25 = 5

Therefore, the point that has a distance of 5 from the point (0, -1) is (0, 4).