To determine which point is a solution to the equation \( y = 2x - 5 \), we will substitute the x-values of each point into the equation and see if the resulting y-value matches the y-value of the point.
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For the point (4, 2): \[ y = 2(4) - 5 = 8 - 5 = 3 \quad (\text{not } 2) \]
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For the point (2, 0): \[ y = 2(2) - 5 = 4 - 5 = -1 \quad (\text{not } 0) \]
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For the point (1, -3): \[ y = 2(1) - 5 = 2 - 5 = -3 \quad (\text{matches } -3) \]
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For the point (-1, -5): \[ y = 2(-1) - 5 = -2 - 5 = -7 \quad (\text{not } -5) \]
The point that is a solution to the equation \( y = 2x - 5 \) is (1, -3).