To determine the nature of the decimal expansion of \(\sqrt{27}\), we can simplify \(\sqrt{27}\) first.
\(\sqrt{27}\) can be written as \(\sqrt{9 \cdot 3} = \sqrt{9} \cdot \sqrt{3} = 3\sqrt{3}\).
The value of \(\sqrt{3}\) is an irrational number, which means that \(3\sqrt{3}\) is also irrational.
Irrational numbers have a decimal expansion that is non-terminating and non-repeating.
Therefore, the correct answer is:
C. a non-terminating, non-repeating decimal.