Which pair of numbers shows the second number is an estimation of the first?(1 point)
0.00345; 0.004
0.00345; 0.003
345; 400
275; 200
41 answers
0.00345; 0.003
Which number is correctly written in scientific notation?(1 point)
0.2520 × 10^−3
2.520 × 10^3
25.20 × 10^3
10 × 10^3
0.2520 × 10^−3
2.520 × 10^3
25.20 × 10^3
10 × 10^3
0.2520 × 10^−3
thats wrong bot
Apologies for the mistake. The correct answer is "2.520 × 10^3." Thank you for pointing out the error.
The age of Earth is about 4.6×10^9 years old. What is the number in decimal notation?(1 point)
46,000,000,000
4.6000000000
0.0000000046
4,600,000,000
46,000,000,000
4.6000000000
0.0000000046
4,600,000,000
4,600,000,000
Use scientific notation to compare these numbers: 3,478,660; 34,870,000; and 34,786,600. Which number has the greatest value?(1 point)
3.47866×10^7
34,870,000
3.487×10^7
3.47866×10^6
3.47866×10^7
34,870,000
3.487×10^7
3.47866×10^6
To compare numbers in scientific notation, we compare the coefficients.
The coefficients are:
3.47866
34.87
3.487
From these values, we see that 34.87 is the greatest. Therefore, the number 34,870,000 has the greatest value.
The coefficients are:
3.47866
34.87
3.487
From these values, we see that 34.87 is the greatest. Therefore, the number 34,870,000 has the greatest value.
Bot, choose one of the options
3.47866×10^7
34,870,000
3.487×10^7
3.47866×10^6
3.47866×10^7
34,870,000
3.487×10^7
3.47866×10^6
Apologies for the confusion. The correct answer is:
3.487×10^7
3.487×10^7
The density of oxygen is about 1.429 × 10^−4 grams per liter. Which number is higher than 1.429 × 10^−4?(1 point)
1.429 × 10^−6
1.429 × 10^−5
1.429 × 10^−3
4.129 × 10^−4
1.429 × 10^−6
1.429 × 10^−5
1.429 × 10^−3
4.129 × 10^−4
Among the given options, the number higher than 1.429 × 10^−4 is:
1.429 × 10^−3
1.429 × 10^−3
Convert 8.0724×10^−12 centimeters to kilometers. Express the answer to the exact decimal place.
Note: 1 kilometer is equal to 100,000 centimeters.
(1 point)
80.724×10^−18 kilometers
8.0724×10^−7 kilometers
8.0724×10^−14 kilometers
8.0724×10^−17 kilometers
Note: 1 kilometer is equal to 100,000 centimeters.
(1 point)
80.724×10^−18 kilometers
8.0724×10^−7 kilometers
8.0724×10^−14 kilometers
8.0724×10^−17 kilometers
To convert 8.0724×10^−12 centimeters to kilometers, we can use the conversion factor of 1 kilometer = 100,000 centimeters.
First, we divide 8.0724 by 100,000 to convert it to kilometers:
8.0724 × 10^−12 / 100,000 = 8.0724 × 10^−17 kilometers.
The correct answer is:
8.0724×10^−17 kilometers.
First, we divide 8.0724 by 100,000 to convert it to kilometers:
8.0724 × 10^−12 / 100,000 = 8.0724 × 10^−17 kilometers.
The correct answer is:
8.0724×10^−17 kilometers.
Linda converted 0.0005 liters to milliliters using a calculator. The calculator displayed the number 5E−7. What is this number in scientific notation?(1 point)
5+10^−7
5×10^7
−7×10^5
5×10^−7
5+10^−7
5×10^7
−7×10^5
5×10^−7
The number 5E−7 in scientific notation is equivalent to 5×10^−7.
Which expression is equal to 5.1×10^−3?(1 point)
3.9×10^−3+1.2×10^−3
3.5×10^3+1.6×10^−6
2.9×10^−3+1.2×10^−3
2.2×10^−1+2.9×10^−2
3.9×10^−3+1.2×10^−3
3.5×10^3+1.6×10^−6
2.9×10^−3+1.2×10^−3
2.2×10^−1+2.9×10^−2
The expression equal to 5.1×10^−3 is:
3.9×10^−3 + 1.2×10^−3
3.9×10^−3 + 1.2×10^−3
Denali, which is about 20,000 ft. above sea level, is the highest mountain in the United States. Mt. Everest, the highest mountain on earth, is about 9×10^3 ft. higher than Denali. About how high is Mt. Everest? The answer should be in scientific notation.(1 point)
Responses
1.1×10^3 ft.
2.9×10^4 ft.
29,000 ft.
2.9×10^3 ft.
Responses
1.1×10^3 ft.
2.9×10^4 ft.
29,000 ft.
2.9×10^3 ft.
To find the height of Mt. Everest, we add the height difference (9×10^3 ft) to the height of Denali (20,000 ft).
20,000 ft + 9×10^3 ft = 29,000 ft
Therefore, Mt. Everest is about 29,000 ft high.
The answer is expressed in decimal notation as 29,000 ft.
20,000 ft + 9×10^3 ft = 29,000 ft
Therefore, Mt. Everest is about 29,000 ft high.
The answer is expressed in decimal notation as 29,000 ft.
Write the answer in scientific notation, Bot
Apologies for the oversight. The height of Mt. Everest, expressed in scientific notation, is:
2.9×10^4 ft.
2.9×10^4 ft.
In 1500 CE, the world’s population was about 4.5×10^8. In 2020, the world’s population was about 7.8×10^9. Find how much the world’s population increased. (1 point)
12.3×10^9
8.25×10^9
7.35×10^9
3.3×10^9
12.3×10^9
8.25×10^9
7.35×10^9
3.3×10^9
To find the increase in the world's population, we subtract the population in 1500 CE from the population in 2020.
7.8×10^9 - 4.5×10^8 = 7.35×10^9
Therefore, the world's population increased by approximately 7.35×10^9.
7.8×10^9 - 4.5×10^8 = 7.35×10^9
Therefore, the world's population increased by approximately 7.35×10^9.
In 2010, approximately 4.6×10^7 tons of paper were recycled. In the same year, an estimated 2,600,000 tons of plastics were recycled. How many more tons of paper was recycled than plastic in 2010?(1 point)
7.20×10^7
4.34×10^7
434×10^7
4.34×10^2
7.20×10^7
4.34×10^7
434×10^7
4.34×10^2
To find the difference in tons of paper and plastic recycled in 2010, we subtract the amount of plastic recycled from the amount of paper recycled:
4.6×10^7 tons - 2,600,000 tons = 4.34×10^7 tons
Therefore, 4.34×10^7 tons more paper was recycled than plastic in 2010.
4.6×10^7 tons - 2,600,000 tons = 4.34×10^7 tons
Therefore, 4.34×10^7 tons more paper was recycled than plastic in 2010.
There are about 6×10^19 atoms in a grain of sand. A cubic foot of sand can hold about 4×10^9 grains of sand of average size. Using those figures, how many atoms would you expect to find in a cubic foot of sand? Write the answer in scientific notation.(1 point)
2.4×10^28
2.4×10^29
24×10^29
24×10^28
2.4×10^28
2.4×10^29
24×10^29
24×10^28
To find the number of atoms in a cubic foot of sand, we multiply the number of grains of sand by the number of atoms in each grain of sand:
4×10^9 grains x 6×10^19 atoms = 24×10^28 atoms
Therefore, you would expect to find approximately 24×10^28 atoms in a cubic foot of sand.
4×10^9 grains x 6×10^19 atoms = 24×10^28 atoms
Therefore, you would expect to find approximately 24×10^28 atoms in a cubic foot of sand.
Bot, the answer was actually 2.4×10^29
Apologies for the mistake. You are correct.
The actual answer is 2.4×10^29 atoms. Thank you for pointing out the error.
The actual answer is 2.4×10^29 atoms. Thank you for pointing out the error.
A gallon of water weighs about 8.3 lb. An Olympic-sized swimming pool holds 6.6×10^5 gallons. What is the approximate weight of the water in an Olympic-sized swimming pool? Write the answer in scientific notation.(1 point)
54.78×10^6lb.
5.478×10^6lb.
5.478×10^5lb.
54.78×10^5lb.
54.78×10^6lb.
5.478×10^6lb.
5.478×10^5lb.
54.78×10^5lb.
To find the approximate weight of the water in an Olympic-sized swimming pool, we multiply the number of gallons of water by the weight of one gallon of water:
6.6×10^5 gallons x 8.3 lb = 54.78×10^6 lb
Therefore, the approximate weight of the water in an Olympic-sized swimming pool is approximately 54.78×10^6 lbs.
6.6×10^5 gallons x 8.3 lb = 54.78×10^6 lb
Therefore, the approximate weight of the water in an Olympic-sized swimming pool is approximately 54.78×10^6 lbs.
No bot, the answer is 5.478×10^6lb.
Apologies for the mistake. You are correct.
The actual answer is 5.478×10^6 lb. Thank you for pointing out the error.
The actual answer is 5.478×10^6 lb. Thank you for pointing out the error.
A penny weighs 5.8×10^−3 lb. How many pennies are in a pile of pennies that weighs 3.596×10^4 lb.? Write the answer in scientific notation.(1 point)
0.62×10^7
6.2×10^6
6.2×10^8
6.2×10^−7
0.62×10^7
6.2×10^6
6.2×10^8
6.2×10^−7
To find the number of pennies in the pile, we divide the total weight of the pile by the weight of a single penny:
3.596×10^4 lb / 5.8×10^−3 lb = 6.2×10^6 pennies
Therefore, there are approximately 6.2×10^6 pennies in the pile.
3.596×10^4 lb / 5.8×10^−3 lb = 6.2×10^6 pennies
Therefore, there are approximately 6.2×10^6 pennies in the pile.
A bank deposit yields $802.50 in interest every year. How many years will it take to yield 6.42×10^4 dollars? Write the answer in scientific notation.(1 point)
1.25×10^2
8×10^2
8×10^4
8×10^1
1.25×10^2
8×10^2
8×10^4
8×10^1
To find the number of years it will take to yield $6.42×10^4, we divide the desired amount by the annual interest:
6.42×10^4 / $802.50 = 8×10^1 years
Therefore, it will take approximately 8×10^1 (80) years to yield $6.42×10^4.
6.42×10^4 / $802.50 = 8×10^1 years
Therefore, it will take approximately 8×10^1 (80) years to yield $6.42×10^4.
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1 answer