To find an ordered pair \((x, y)\) that is a solution to the equation \(3x + 2y = 11\), we can choose a value for \(x\) and solve for \(y\), or vice versa.
Let's choose \(x = 1\):
\[ 3(1) + 2y = 11 \] \[ 3 + 2y = 11 \] \[ 2y = 11 - 3 \] \[ 2y = 8 \] \[ y = 4 \]
So one solution is \((1, 4)\).
You can check this solution by plugging \(x = 1\) and \(y = 4\) back into the original equation:
\[ 3(1) + 2(4) = 3 + 8 = 11 \]
Thus, the ordered pair \((1, 4)\) is indeed a solution to the equation \(3x + 2y = 11\).