y x^2 - 3 y = 12
y (x^2 - 3) = 12
y = 12 / (x^2-3)
if x = 0 , y = -4 ok
if x = 4 , y = 12/13 oops
etc
Which ordered pair is not in the inverse of the relation given by xy^2-3x = 12?
(A) (0, -4)
(B) (4, 1)
(C) (3, 2)
(D) (2, 12)
(E) (1, -6)
1 answer