To determine which ordered pair is a solution of the linear system, we need to substitute the x and y values of each ordered pair into the equations and see if they satisfy the equations.
Let's substitute the x and y values of each option into the equations:
For (3/2, 7/4):
y = 1/2(3/2) + 1 = 3/4 + 1 = 7/4
y = 3/2(3/2) + 4 = 9/4 + 4 = 25/4
Since both equations are satisfied, (3/2, 7/4) is a solution of the linear system.
For (-3 - 1/2):
y = 1/2(-3) + 1 = -3/2 + 1 = -1/2
y = 3/2(-3) + 4 = -9/2 + 4 = -1/2
Since both equations are satisfied, (-3 - 1/2) is also a solution of the linear system.
For (0, 1):
y = 1/2(0) + 1 = 0 + 1 = 1
y = 3/2(0) + 4 = 0 + 4 = 4
The equations are not satisfied, so (0, 1) is not a solution of the linear system.
For (3, 5/2):
y = 1/2(3) + 1 = 3/2 + 1 = 5/2
y = 3/2(3) + 4 = 9/2 + 4 = 13/2
Since both equations are satisfied, (3, 5/2) is a solution of the linear system.
Therefore, the ordered pairs (3/2, 7/4) and (3, 5/2) are solutions of the linear system.
Which ordered pair is a solution of the linear system shown?
y=1/2x+1
y=3/2x+4
(3/2,7/4)
(-3 - 1/2)
(0,1)
(3,5/2)
y=1/2x+1
1 answer