To simplify the expression \(\frac{9^{-4}}{(-3)^{-8}}\), we can use the properties of exponents.
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Recall that \(a^{-n} = \frac{1}{a^n}\), so we can rewrite the expression: \[ \frac{9^{-4}}{(-3)^{-8}} = \frac{1}{9^4} \div \frac{1}{(-3)^8} = \frac{(-3)^8}{9^4} \]
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Now we can calculate the powers:
- \(9 = 3^2\), therefore: \[ 9^4 = (3^2)^4 = 3^{8} \]
- \((-3)^8 = 3^8\) (since a negative number raised to an even power is positive).
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Substitute back: \[ \frac{(-3)^8}{9^4} = \frac{3^8}{3^8} = 1 \]
Thus, the equivalent expression is: \[ \boxed{1} \]
So the correct answer is A. 1.