To find the last row of the augmented matrix corresponding to the given system of equations, we need to analyze the equations provided:
- \(6x - y + 4z = 6\)
- \(12x + y - 2z = 12\)
- \(-24x + y + 3z = -24\)
In matrix form, the augmented matrix will look like this:
\[ \begin{bmatrix} 6 & -1 & 4 & | & 6 \ 12 & 1 & -2 & | & 12 \ -24 & 1 & 3 & | & -24 \end{bmatrix} \]
The last row of the augmented matrix corresponds to the third equation. Therefore, the last row will be:
\[ [-24 \quad 1 \quad 3 \quad | \quad -24] \]
This representation can be put into the following options:
- Option A: \([-24 \quad 1 \quad 3 \quad -24]\)
Hence, the correct option that accurately re-creates the last row of the augmented matrix is: [–2413–24].