Which one of the following is NOT a property of equipotential surface?
No work is done in moving a test charge from one point to another on an equipotential surface.
The electric field is always perpendicular to an equipotential surface.
None of the above
The direction of the equipotential surface is from low potential to high potential.
Two equipotential surfaces can never intersect.
5 answers
The direction of the equipotential surface is from low potential to high potential.
Figure below shows an electric dipole in a uniform electric field with magnitude 10 cross times 10 to the power of 5 N/C directed parallel to the plane of the figure.The electric dipole consists of two charges q subscript 1 equals plus e and q subscript 2 equals negative e space left parenthesis e equals 1.6 cross times 10 to the power of negative 19 end exponent right parenthesis, which both lie in the plane and separated by a distance 0.12 space n text m end text
q6.png
Calculate the magnitude of the torque
q6.png
Calculate the magnitude of the torque
The torque on an electric dipole in a uniform electric field is given by the formula:
τ = pE sinθ
where τ is the torque, p is the magnitude of the dipole moment, E is the magnitude of the electric field, and θ is the angle between the dipole moment and the electric field.
In this case, we are given E = 10^5 N/C and the distance between the charges is 0.12 m. The magnitude of the dipole moment is given by:
p = qd
where q is the charge and d is the separation between the charges.
Using q = 1.6 x 10^-19 C and d = 0.12 m, we can calculate the magnitude of the dipole moment:
p = (1.6 x 10^-19 C)(0.12 m) = 1.92 x 10^-20 C·m
The angle between the dipole moment and the electric field is 90 degrees since they are parallel to each other.
Now we can substitute the values into the formula for torque:
τ = (1.92 x 10^-20 C·m)(10^5 N/C)(sin 90°)
Since sin 90° = 1, the torque simplifies to:
τ = 1.92 x 10^-20 C·m·N
Therefore, the magnitude of the torque is 1.92 x 10^-20 C·m·N.
τ = pE sinθ
where τ is the torque, p is the magnitude of the dipole moment, E is the magnitude of the electric field, and θ is the angle between the dipole moment and the electric field.
In this case, we are given E = 10^5 N/C and the distance between the charges is 0.12 m. The magnitude of the dipole moment is given by:
p = qd
where q is the charge and d is the separation between the charges.
Using q = 1.6 x 10^-19 C and d = 0.12 m, we can calculate the magnitude of the dipole moment:
p = (1.6 x 10^-19 C)(0.12 m) = 1.92 x 10^-20 C·m
The angle between the dipole moment and the electric field is 90 degrees since they are parallel to each other.
Now we can substitute the values into the formula for torque:
τ = (1.92 x 10^-20 C·m)(10^5 N/C)(sin 90°)
Since sin 90° = 1, the torque simplifies to:
τ = 1.92 x 10^-20 C·m·N
Therefore, the magnitude of the torque is 1.92 x 10^-20 C·m·N.
Figure below shows an electric dipole in a uniform electric field with magnitude 10 cross times 10 to the power of 5 N/C directed parallel to the plane of the figure.The electric dipole consists of two charges q subscript 1 equals plus e and q subscript 2 equals negative e space left parenthesis e equals 1.6 cross times 10 to the power of negative 19 end exponent right parenthesis, which both lie in the plane and separated by a distance 0.12 space n text m end text
q6.png
Calculate the magnitude of the torque
1.92 cross times 10 to the power of negative 29 end exponent space text Nm end text
None of the above
1.23 cross times 10 to the power of negative 23 end exponent space text Nm end text
0 space text Nm end text
1.32 cross times 10 to the power of negative 33 end exponent space text Nm end text
q6.png
Calculate the magnitude of the torque
1.92 cross times 10 to the power of negative 29 end exponent space text Nm end text
None of the above
1.23 cross times 10 to the power of negative 23 end exponent space text Nm end text
0 space text Nm end text
1.32 cross times 10 to the power of negative 33 end exponent space text Nm end text
The magnitude of the torque on an electric dipole in a uniform electric field is given by the formula:
τ = pE sinθ
where τ is the torque, p is the magnitude of the dipole moment, E is the magnitude of the electric field, and θ is the angle between the dipole moment and the electric field.
In this case, we are given E = 10^5 N/C and the distance between the charges is 0.12 m. The magnitude of the dipole moment is given by:
p = qd
where q is the charge and d is the separation between the charges.
Using q = 1.6 x 10^-19 C and d = 0.12 m, we can calculate the magnitude of the dipole moment:
p = (1.6 x 10^-19 C)(0.12 m) = 1.92 x 10^-20 C·m
The angle between the dipole moment and the electric field is 90 degrees since they are parallel to each other.
Now we can substitute the values into the formula for torque:
τ = (1.92 x 10^-20 C·m)(10^5 N/C)(sin 90°)
Since sin 90° = 1, the torque simplifies to:
τ = 1.92 x 10^-15 N·m
Therefore, the magnitude of the torque is 1.92 x 10^-15 N·m.
τ = pE sinθ
where τ is the torque, p is the magnitude of the dipole moment, E is the magnitude of the electric field, and θ is the angle between the dipole moment and the electric field.
In this case, we are given E = 10^5 N/C and the distance between the charges is 0.12 m. The magnitude of the dipole moment is given by:
p = qd
where q is the charge and d is the separation between the charges.
Using q = 1.6 x 10^-19 C and d = 0.12 m, we can calculate the magnitude of the dipole moment:
p = (1.6 x 10^-19 C)(0.12 m) = 1.92 x 10^-20 C·m
The angle between the dipole moment and the electric field is 90 degrees since they are parallel to each other.
Now we can substitute the values into the formula for torque:
τ = (1.92 x 10^-20 C·m)(10^5 N/C)(sin 90°)
Since sin 90° = 1, the torque simplifies to:
τ = 1.92 x 10^-15 N·m
Therefore, the magnitude of the torque is 1.92 x 10^-15 N·m.
1 answer