sin^2x = 1/2
sinx = ±1/√2
so you now have the reference angle of π/4, in all four quadrants.
Which of these is a possible solution for sin^2 x-1/2 =0 in the interval x ∈ [0,2pi]?
a. x = pi/4
b. x = 7pi/4
c. x = 5pi/4
d. all of the above
2 answers
xcv
1 answer