To determine which graph shows that the linear system \(y = x - 2\) and \(3x - 3y = 6\) has an infinite number of solutions, we need to check whether the two equations represent the same line.
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The equation \(y = x - 2\) is already in slope-intercept form (\(y = mx + b\)), where the slope \(m = 1\) and the y-intercept \(b = -2\).
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The second equation \(3x - 3y = 6\) can be rearranged to slope-intercept form. Start by solving for \(y\): \[ 3x - 3y = 6 \ -3y = -3x + 6 \ y = x - 2. \]
Now we see that both equations \(y = x - 2\) and \(y = x - 2\) are indeed the same line. Since they represent the same line, the system has an infinite number of solutions.
Therefore, the correct graph will be the one showing a solid line for \(y = x - 2\) and the same line drawn over it, confirming they are the same line. This would correspond to the fourth graph you described: "Two parallel lines are plotted on the plane," but one of those lines is not actually parallel because it overlaps, indicating that the two equations describe the same line.
The graph you are looking for should show:
- A line representing \(y = x - 2\)
- Another line coinciding with it (i.e., the same line).
If you do not see any lines that represent only one unique line, that would indicate an infinite number of solutions. Thus, confirm that a solid downward slanting line is drawn, and you should choose the option that reflects that.