Which of the numbers 4, 5, and 6 is a solution of 3x + 2 ≥ 20 ?
respones
4
5
6
which one is it
3 answers
6
can you explain
To determine which of the numbers 4, 5, or 6 is a solution to the inequality 3x + 2 ≥ 20, we need to substitute each number into the inequality and see if it makes the inequality true.
Let's test each number:
1. For x = 4: 3(4) + 2 = 12 + 2 = 14, which is not greater than or equal to 20. Therefore, 4 is not a solution.
2. For x = 5: 3(5) + 2 = 15 + 2 = 17, which is not greater than or equal to 20. Therefore, 5 is not a solution.
3. For x = 6: 3(6) + 2 = 18 + 2 = 20, which is equal to 20. Therefore, 6 is a solution.
Therefore, the number 6 is the solution to the inequality 3x + 2 ≥ 20.
Let's test each number:
1. For x = 4: 3(4) + 2 = 12 + 2 = 14, which is not greater than or equal to 20. Therefore, 4 is not a solution.
2. For x = 5: 3(5) + 2 = 15 + 2 = 17, which is not greater than or equal to 20. Therefore, 5 is not a solution.
3. For x = 6: 3(6) + 2 = 18 + 2 = 20, which is equal to 20. Therefore, 6 is a solution.
Therefore, the number 6 is the solution to the inequality 3x + 2 ≥ 20.
1 answer