Which of the numbers 1, 2, and 3 is a solution of 2z + 1 ≥ 7?

Answer 1

To find out if a number is a solution to the inequality 2z + 1 ≥ 7, we first need to substitute each number into the inequality and see if it holds true.

For z = 1:
2(1) + 1 ≥ 7
2 + 1 ≥ 7
3 ≥ 7
This statement is false, so 1 is not a solution to the inequality.

For z = 2:
2(2) + 1 ≥ 7
4 + 1 ≥ 7
5 ≥ 7
This statement is false, so 2 is not a solution to the inequality.

For z = 3:
2(3) + 1 ≥ 7
6 + 1 ≥ 7
7 ≥ 7
This statement is true, so 3 is a solution to the inequality.

Therefore, the number 3 is the only solution to the inequality 2z + 1 ≥ 7.