Plug in each number and check:
1. 2(1) + 1 ≥ 7
2 + 1 ≥ 7
3 ≥ 7 (False)
2. 2(2) + 1 ≥ 7
4 + 1 ≥ 7
5 ≥ 7 (False)
3. 2(3) + 1 ≥ 7
6 + 1 ≥ 7
7 ≥ 7 (True)
Therefore, the number 3 is a solution to the inequality 2x + 1 ≥ 7.
Which of the numbers 1, 2, and 3 is a solution of 2x+1≥7
1 answer