To find out which number is a solution of the inequality 2x + 1 ≥ 7, we plug in each number into the inequality and see which one makes the inequality true.
Let's start with x = 1:
2(1) + 1 ≥ 7
2 + 1 ≥ 7
3 ≥ 7
As 3 is not greater than or equal to 7, x = 1 is not a solution.
Next, let's try x = 2:
2(2) + 1 ≥ 7
4 + 1 ≥ 7
5 ≥ 7
As 5 is not greater than or equal to 7, x = 2 is also not a solution.
Finally, we try x = 3:
2(3) + 1 ≥ 7
6 + 1 ≥ 7
7 ≥ 7
As 7 is indeed greater than or equal to 7, x = 3 is a solution.
Therefore, the number to put in the box would be 3.
Which of the numbers 1, 2, and 3 is a solution of 2x+1≥7 ?(1 point)
AND WHAT NUMBER WOULD I PUT IN THE BOX?
1 answer