To solve the inequality \( \sqrt{4x + 1} \leq 5.83 \), we will first square both sides to eliminate the square root (keeping in mind this only works because both sides are non-negative):
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Start with the original inequality: \[ \sqrt{4x + 1} \leq 5.83 \]
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Square both sides: \[ 4x + 1 \leq (5.83)^2 \] \[ 4x + 1 \leq 33.9889 \]
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Subtract 1 from both sides: \[ 4x \leq 32.9889 \]
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Divide both sides by 4: \[ x \leq 8.247225 \]
Now, we need to find which of the given options for \( x \) satisfies this inequality:
- \( 8 \) is less than 8.247225 (valid)
- \( 9.5 \) is greater than 8.247225 (invalid)
- \( 9 \) is greater than 8.247225 (invalid)
- \( 10 \) is greater than 8.247225 (invalid)
The only value that makes the inequality true is: 8