To solve the quadratic equation \( 7x^2 = 56x \), we first need to rewrite it in standard form, factor it, and then find the solutions. Let's go through the options.
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Put the quadratic in standard form:
- Start by moving all terms to one side: \( 7x^2 - 56x = 0 \).
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Factor out the GCF (Greatest Common Factor):
- The GCF of \( 7x^2 \) and \( -56x \) is \( 7x \).
- Factoring it out gives: \( 7x(x - 8) = 0 \).
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Set each factor equal to zero:
- Setting \( 7x = 0 \) gives \( x = 0 \).
- Setting \( x - 8 = 0 \) gives \( x = 8 \).
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The solutions are:
- The solutions are \( x = 0 \) and \( x = 8 \).
From the options listed, the second option correctly follows these steps:
- Put the quadratic in standard form: \( 7x^2 - 56x = 0 \)
- Factor out the GCF: \( 7x(x - 8) = 0 \)
- Set each factor equal to zero: \( 7x = 0 \) and \( x - 8 = 0 \)
- The solutions are: \( x = 0 \) and \( x = 8 \)
So, the correct response is:
Put the quadratic in standard form \( 7x^2−56x=0 \)
Factor out the GCF \( 7x(x−8)=0 \)
Set each factor equal to zero \( 7x=0 \) and \( x−8=0 \)
The solutions are \( x=0 \) and \( x=8 \)