To factor the given quadratic equation \(7x^2 = 56x\), we first need to rearrange it into standard form and then follow the correct steps.
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Put the quadratic in standard form: We subtract \(56x\) from both sides, leading to: \[ 7x^2 - 56x = 0 \]
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Factor out the GCF: The greatest common factor (GCF) of \(7x^2\) and \(56x\) is \(7x\). Factoring this out gives us: \[ 7x(x - 8) = 0 \]
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Set each factor equal to zero: We then set each factor equal to zero: \[ 7x = 0 \quad \text{and} \quad x - 8 = 0 \]
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The solutions are: Solving these gives us: \[ x = 0 \quad \text{and} \quad x = 8 \]
The correct response that matches these steps is:
Put the quadratic in standard form: \(7x^2 - 56x = 0\)
Factor out the GCF: \(7x(x - 8) = 0\)
Set each factor equal to zero: \(7x = 0\) and \(x - 8 = 0\)
The solutions are: \(x = 0\) and \(x = 8\)
This corresponds to the second option from your list.