Which of the following tables shows that y=kf(x)

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results in the parent function y=|x+4|
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being vertically stretched by a k factor of 3?(1 point)
Responses

Responses x y=kf(x) 𝑦 = 𝑘 𝑓 ( 𝑥 ) 0 4 1 5 2 6 x y equals k f left parenthesis x right parenthesis 0 4 1 5 2 6 x y=kf(x) 𝑦 = 𝑘 𝑓 ( 𝑥 ) 0 1.3 1 1.7 2 2 x y equals k f left parenthesis x right parenthesis 0 1.3 1 1.7 2 2 x y=kf(x) 𝑦 = 𝑘 𝑓 ( 𝑥 ) 0 −12 − 12 1 −15 − 15 2 −18 − 18 x y equals k f left parenthesis x right parenthesis 0 negative 12 1 negative 15 2 negative 18 x y=kf(x) 𝑦 = 𝑘 𝑓 ( 𝑥 ) 0 12 1 15 2 18

1 answer

To determine which table corresponds to the function \( y = kf(x) \), where the parent function is \( f(x) = |x + 4| \) and \( k = 3 \), we need to evaluate how that affects the output values.

The parent function \( f(x) = |x + 4| \) produces certain output values that will then be scaled by a factor of 3. Let's first compute the outputs of the parent function for the provided \( x \) values:

  1. For \( x = 0 \): \[ f(0) = |0 + 4| = |4| = 4 \quad \Rightarrow \quad y = 3 \cdot 4 = 12 \]

  2. For \( x = 1 \): \[ f(1) = |1 + 4| = |5| = 5 \quad \Rightarrow \quad y = 3 \cdot 5 = 15 \]

  3. For \( x = 2 \): \[ f(2) = |2 + 4| = |6| = 6 \quad \Rightarrow \quad y = 3 \cdot 6 = 18 \]

The resulting values we computed from the function \( y = 3f(x) \) for our chosen \( x \) values are:

  • At \( x = 0 \), \( y = 12 \)
  • At \( x = 1 \), \( y = 15 \)
  • At \( x = 2 \), \( y = 18 \)

Now, let's analyze the given options to find a table that provides these output values:

  1. \( y = kf(x) \)
  • \( x=0, y=4 \)
  • \( x=1, y=5 \)
  • \( x=2, y=6 \)
  1. \( y = kf(x) \)
  • \( x=0, y=1.3 \)
  • \( x=1, y=1.7 \)
  • \( x=2, y=2 \)
  1. \( y = kf(x) \)
  • \( x=0, y=-12 \)
  • \( x=1, y=-15 \)
  • \( x=2, y=-18 \)
  1. \( y = kf(x) \)
  • \( x=0, y=12 \)
  • \( x=1, y=15 \)
  • \( x=2, y=18 \)

The fourth table (the last option) is the only one that shows \( y \) values of \( 12, 15, \) and \( 18 \) corresponding to \( x \) values of \( 0, 1, 2 \), respectively, which matches the expected outputs.

Thus, the correct response is:

The fourth table: \( x \) \( y = kf(x) \)

  • \( 0 \quad 12 \)
  • \( 1 \quad 15 \)
  • \( 2 \quad 18 \)