To determine which of the given tables represents a proportional relationship, we need to check if the ratio of \(y\) to \(x\) (i.e., \( \frac{y}{x} \)) is constant for all pairs in each table.
Let's analyze each option:
A. \[ \begin{array}{c|c} x & y \ \hline 4 & 6 \quad \frac{6}{4} = 1.5 \ 6 & 9 \quad \frac{9}{6} = 1.5 \ 8 & 12 \quad \frac{12}{8} = 1.5 \ 10 & 15 \quad \frac{15}{10} = 1.5 \ \end{array} \] The ratio \( \frac{y}{x} = 1.5 \) is constant in this table.
B. \[ \begin{array}{c|c} x & y \ \hline 1 & 0 \quad \frac{0}{1} = 0 \ 4 & 3 \quad \frac{3}{4} = 0.75 \ 7 & 6 \quad \frac{6}{7} \approx 0.857 \ 10 & 9 \quad \frac{9}{10} = 0.9 \ \end{array} \] The ratios are not constant.
C. \[ \begin{array}{c|c} x & y \ \hline 2 & 3 \quad \frac{3}{2} = 1.5 \ 4 & 4 \quad \frac{4}{4} = 1 \ 6 & 5 \quad \frac{5}{6} \approx 0.833 \ 8 & 6 \quad \frac{6}{8} = 0.75 \ \end{array} \] The ratios are not constant.
D. \[ \begin{array}{c|c} x & y \ \hline 2 & 3 \quad \frac{3}{2} = 1.5 \ 3 & 6 \quad \frac{6}{3} = 2 \ 4 & 9 \quad \frac{9}{4} = 2.25 \ 5 & 12 \quad \frac{12}{5} = 2.4 \ \end{array} \] The ratios are not constant.
The only table that represents a proportional relationship is Option A:
\[ \begin{array}{c|c} x & y \ \hline 4 & 6 \ 6 & 9 \ 8 & 12 \ 10 & 15 \ \end{array} \]
Thus, A is the answer.