Which of the following systems of equations has the solution (4, 0)? %C2%A0 (1 point) Responses y=−32x−2 ��� = − 3 2 ��� − 2 %C2%A0and%C2%A02x−y=−5 2 ��� − ��� = − 5 y is equal to negative 3 over 2 x minus 2%C2%A0and%C2%A02 x minus y is equal to negative 5 y=−x+4 ��� = − ��� + 4 %C2%A0and%C2%A0−2=−y%C2%A0−12x − 2 = − ��� %C2%A0 − 1 2 ��� y is equal to negative x plus 4%C2%A0and%C2%A0−2=−y%C2%A0−12x − 2 = − ��� %C2%A0 − 1 2 ��� 2x−y=−5 2 ��� − ��� = − 5 %C2%A0and%C2%A0x+2y=10 ��� + 2 ��� = 10 2 x minus y is equal to negative 5%C2%A0and%C2%A0x plus 2 y is equal to 10 x−4y=8 ��� − 4 ��� = 8 %C2%A0and%C2%A03x+10=−2y 3 ��� + 10 = − 2 ��� x minus 4 y is equal to 8%C2%A0and%C2%A03 x plus 10 is equal to negative 2 y

Answer 1

The system of equations that has the solution (4, 0) is:

y=−3/2x−2 and 2x−y=−5

Plugging in x=4, we get:

y=−3/2(4)−2
y=−6−2
y=-8

Therefore, the solution to the system of equations is (4, -8).