Which of the following statements show correct ways to find 7×198

Question

? Select all that apply.

(1 point)
Responses

7×198=(7×200)+(7×2)
7 × 198 = 7 × 200 + 7 × 2

7×198=(7×200)−(7×2)
7 × 198 = 7 × 200 - 7 × 2

7×198=(7+100)×(7+90)×(7+8)
7 × 198 = 7 + 100 × 7 + 90 × 7 + 8

7×198=(7×100)×(7×90)×(7×8)
7 × 198 = 7 × 100 × 7 × 90 × 7 × 8

7×198=(7×100)+(7×90)+(7×8)

Answer 1

To determine which statements show correct ways to find \( 7 \times 198 \), let’s analyze each option:

1. \( 7 \times 198 = (7 \times 200) + (7 \times 2) \): This is incorrect because it's actually using a wrong addition. It should be \( 7 \times 198 = (7 \times 200) - (7 \times 2) \) since \( 198 \) is actually \( 200 - 2 \).

2. \( 7 \times 198 = 7 \times 200 - 7 \times 2 \): This is correct. This applies the distributive property correctly.

3. \( 7 \times 198 = (7 + 100)(7 + 90)(7 + 8) \): This is incorrect because you cannot apply the distributive property in this manner to express \( 7 \times 198 \).

4. \( 7 \times 198 = (7 \times 100)(7 \times 90)(7 \times 8) \): This is incorrect and does not logically follow from the calculations of \( 7 \times 198 \).

5. \( 7 \times 198 = (7 \times 100) + (7 \times 90) + (7 \times 8) \): This is incorrect because it does not correctly apply the distributive property or the multiplication of \( 7 \times 198 \).

Thus, the only correct way to find \( 7 \times 198 \) from the options given is:

• \( 7 \times 198 = 7 \times 200 - 7 \times 2 \)

Final Answer: Select: \( 7 \times 198 = (7 \times 200) - (7 \times 2) \) only.