This sequence is \( 81, 27, 9, 3, 1, \ldots \). To find the value of \( a_7 \), we first need to determine whether the sequence is arithmetic or geometric.
Step 1: Identify the type of sequence
-
Check if it is geometric:
Calculate the ratio between consecutive terms:
- \( \frac{27}{81} = \frac{1}{3} \)
- \( \frac{9}{27} = \frac{1}{3} \)
- \( \frac{3}{9} = \frac{1}{3} \)
- \( \frac{1}{3} = \frac{1}{3} \)
The common ratio is consistent: \( r = \frac{1}{3} \).
Step 2: Use the formula for the \( n \)-th term of a geometric sequence
The formula for the \( n \)-th term of a geometric sequence is given by:
\[
a_n = a_1 \cdot r^{(n-1)}
\]
Where:
- \( a_1 \) is the first term
- \( r \) is the common ratio
- \( n \) is the term number
Step 3: Calculate \( a_7 \)
In this case:
- \( a_1 = 81 \)
- \( r = \frac{1}{3} \)
- We want to find \( a_7 \).
Using the formula:
\[
a_7 = 81 \cdot \left(\frac{1}{3}\right)^{7-1}
\]
\[
a_7 = 81 \cdot \left(\frac{1}{3}\right)^{6}
\]
\[
= 81 \cdot \frac{1}{729}
\]
\[
= \frac{81}{729}
\]
\[
= \frac{1}{9}
\]
Therefore, \( a_7 = \frac{1}{9} \).
The correct response is:
a7 = 1/9 (A sub 7 is equal to 1 ninth).