A triple bond has two degrees of unsaturation, each. So, you have four degrees of unsaturation.
So use the following equation:
Degrees of unsaturation=(2n+2-H)/2
You know that you have four degrees of unsaturation, and you know that you must have 6 carbons (n). So, solve for the number of hydorgens that you will have.
4=(2(6)+2-H)/2
8=12+2-H
-6=-H
H=6
So, C6H6
Which of the following six-carbon molecules can be a straight-chain alkyne with two triple bonds and no double bonds?
C6H4
C6H6
C6H8
C6H10
1 answer
1 answer