Which of the following six-carbon molecules can be a straight-chain alkyne with two triple bonds and no double bonds?

C6H4
C6H6
C6H8
C6H10

1 answer

A triple bond has two degrees of unsaturation, each. So, you have four degrees of unsaturation.

So use the following equation:

Degrees of unsaturation=(2n+2-H)/2

You know that you have four degrees of unsaturation, and you know that you must have 6 carbons (n). So, solve for the number of hydorgens that you will have.

4=(2(6)+2-H)/2

8=12+2-H
-6=-H
H=6

So, C6H6