Which of the following shows a system of equations equivalent to 2x+7y=14 and 4x+5y=10 ?(1 point)

Responses

2x+7y=14 and 8x+10y=20
2 x plus 7 y equals 14 and 8 x plus 10 y equals 20

4x+14y=28 and 8x+10y=10
4 x plus 14 y equals 28 and 8 x plus 10 y equals 10

4x+14y=14 and 4x+5y=10
4 x plus 14 y equals 14 and 4 x plus 5 y equals 10

2x+7y=14 and 2x+5y=5
2 x plus 7 y equals 14 and 2 x plus 5 y equals 5

1 answer

To determine which of the options shows a system of equations equivalent to \(2x + 7y = 14\) and \(4x + 5y = 10\), we need to check if the alternative equations can be derived from these original equations.

  1. For \(2x + 7y = 14\): If we multiply this equation by 2, we get: \[ 2(2x + 7y) = 2(14) \Rightarrow 4x + 14y = 28 \]

  2. For \(4x + 5y = 10\): If we multiply this equation by 2, we get: \[ 2(4x + 5y) = 2(10) \Rightarrow 8x + 10y = 20 \]

Thus, the equivalent system from the original equations can be found as: \[ 4x + 14y = 28 \quad \text{and} \quad 8x + 10y = 20 \]

Hence, the correct answer is: 4x + 14y = 28 and 8x + 10y = 20.