Which of the following responses demonstrates that polynomials form a closed system under multiplication?(1 point) Responses x^2+2x+1 x squared plus 2 x plus 1 \left(\frac{x^2}{2}\right)\left(\frac{1}{x}\right) left parenthesis Start Fraction x squared over 2 End Fraction right parenthesis left parenthesis Start Fraction 1 over x End Fraction right parenthesis \left(x^2+1\right)\left(x-\frac{1}{2}\right) left parenthesis x squared plus 1 right parenthesis left parenthesis x minus Start Fraction 1 over 2 End Fraction right parenthesis \left(\sqrt{x}\right)\left(x+1\right)

1 answer

To determine which response demonstrates that polynomials form a closed system under multiplication, we need to multiply the expressions provided and check if the result is a polynomial.

  1. Response: \( x^2 + 2x + 1 \)

    • This is already a polynomial.
  2. Response: \( \left(\frac{x^2}{2}\right)\left(\frac{1}{x}\right) \)

    • When we multiply: \[ \frac{x^2}{2} \cdot \frac{1}{x} = \frac{x^{2}}{2x} = \frac{x}{2} \]
    • This is a polynomial (specifically a linear polynomial).
  3. Response: \( \left(x^2 + 1\right)\left(x - \frac{1}{2}\right) \)

    • When we expand: \[ (x^2 + 1)(x - \frac{1}{2}) = x^3 - \frac{1}{2}x^2 + x - \frac{1}{2} \]
    • This is a polynomial (specifically a cubic polynomial).
  4. Response: \( \left(\sqrt{x}\right)\left(x + 1\right) \)

    • When we multiply: \[ \sqrt{x} \cdot (x + 1) = x^{\frac{3}{2}} + \sqrt{x} \]
    • This result is not a polynomial, as polynomials do not allow for fractional exponents.

Conclusion: The responses that demonstrate that polynomials form a closed system under multiplication are:

  • \( x^2 + 2x + 1 \)
  • \( \left(\frac{x^2}{2}\right)\left(\frac{1}{x}\right) \)
  • \( \left(x^2 + 1\right)\left(x - \frac{1}{2}\right) \)

However, the first two responses specifically show that polynomials can be multiplied to produce a valid polynomial product, confirming closure. The best example to select from the provided options is the one involving \( \left(x^2 + 1\right)\left(x - \frac{1}{2}\right) \) because it clearly involves the multiplication of two polynomials resulting in another polynomial.