nope. d
a relation is not a function if for some x=h, there is more than one pair with that x-value.
according to d,
f(4) = 4
f(4) = 1
both cannot be true for a function.
All the other relations have distinct x values for all the pairs. They are functions.
Which of the following relations is not a function?
(8, 4), (-5, 2), (4, 1), (-6, 2)
(-5, 4), (4, 2), (8, 1), (-6, 5)
(-6, 4), (4, 3), (-5, 1), (8, 2)
(4, 4), (-5, 2), (4, 1), (-6, 2)
my answer is b
1 answer