Which of the following re-expresses the negative square root −6−20−−−−√ as a complex number in the standard form a+bi ?(1 point)

Responses

−125–√
negative 12 Start Root 5 End Root

−12i5–√
negative 12 i Start Root 5 End Root

−125i−−√
negative 12 Start Root 5 i End Root

2i5–√

1 answer

To re-express \(-\sqrt{-20}\) as a complex number in standard form \(a + bi\), we first recognize that \(-20\) can be expressed as \(20 \cdot (-1)\).

Thus, we can write:

\[ -\sqrt{-20} = -\sqrt{20 \cdot (-1)} = -\sqrt{20} \cdot \sqrt{-1} \]

Knowing that \(\sqrt{-1} = i\), we can further simplify:

\[ -\sqrt{-20} = -\sqrt{20} \cdot i \]

Next, we can simplify \(\sqrt{20}\):

\[ \sqrt{20} = \sqrt{4 \cdot 5} = \sqrt{4} \cdot \sqrt{5} = 2\sqrt{5} \]

Substituting this back into our equation gives:

\[ -\sqrt{-20} = -2\sqrt{5} \cdot i \]

This can be expressed in standard form \(a + bi\) as:

\[ 0 - 2\sqrt{5} i \]

This corresponds to \(a = 0\) and \(b = -2\sqrt{5}\).

Now, looking for the correct response among the given options, we see that the correct result is:

\(-2\sqrt{5}i\)

So the correct response is:

negative 12 i Start Root 5 End Root (which is \(-2\sqrt{5} i\)).

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