To have x = -7 and x = 3 as the only two real zeros, the quartic function must have the following factors:
(x + 7) and (x - 3)
Therefore, the quartic function can be written as:
f(x) = (x + 7)(x - 3)
Expanding this out gives:
f(x) = x^2 - 3x + 7x - 21
Simplifying further:
f(x) = x^2 + 4x - 21
Therefore, the quartic function with x = -7 and x = 3 as its only two real zeros is f(x) = x^2 + 4x - 21.
which of the following quartic functions has x=-7 and x=3 as its only two real zeros?
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