To find which point shows a solution to the simultaneous inequalities \( y > 12x + 5 \) and \( y < -2x + 1 \), we need to check each point against both inequalities.
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Point (1, 5.5)
- Check \( y > 12x + 5 \):
- \( 5.5 > 12(1) + 5 \)
- \( 5.5 > 12 + 5 \)
- \( 5.5 > 17 \) (False)
- This point does not satisfy the first inequality.
- Check \( y > 12x + 5 \):
-
Point (-1.6, 4.2)
- Check \( y > 12x + 5 \):
- \( 4.2 > 12(-1.6) + 5 \)
- \( 4.2 > -19.2 + 5 \)
- \( 4.2 > -14.2 \) (True)
- Check \( y < -2x + 1 \):
- \( 4.2 < -2(-1.6) + 1 \)
- \( 4.2 < 3.2 + 1 \)
- \( 4.2 < 4.2 \) (False)
- This point does not satisfy the second inequality.
- Check \( y > 12x + 5 \):
-
Point (-5, 5)
- Check \( y > 12x + 5 \):
- \( 5 > 12(-5) + 5 \)
- \( 5 > -60 + 5 \)
- \( 5 > -55 \) (True)
- Check \( y < -2x + 1 \):
- \( 5 < -2(-5) + 1 \)
- \( 5 < 10 + 1 \)
- \( 5 < 11 \) (True)
- This point satisfies both inequalities.
- Check \( y > 12x + 5 \):
-
Point (4, 8)
- Check \( y > 12x + 5 \):
- \( 8 > 12(4) + 5 \)
- \( 8 > 48 + 5 \)
- \( 8 > 53 \) (False)
- This point does not satisfy the first inequality.
- Check \( y > 12x + 5 \):
After evaluating all points, the point that satisfies both inequalities is (-5, 5).