To determine which point does not belong to the graph of the function \( y = (x+1)^3 - 2 \), we will evaluate the function at each x-value given in the points and see if the corresponding y-value matches.
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For the point \((-2, -3)\): \[ y = (-2 + 1)^3 - 2 = (-1)^3 - 2 = -1 - 2 = -3 \] The point \((-2, -3)\) is on the graph.
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For the point \((-3, 6)\): \[ y = (-3 + 1)^3 - 2 = (-2)^3 - 2 = -8 - 2 = -10 \] The point \((-3, 6)\) is not on the graph since the calculated y-value is -10, not 6.
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For the point \((0, -1)\): \[ y = (0 + 1)^3 - 2 = (1)^3 - 2 = 1 - 2 = -1 \] The point \((0, -1)\) is on the graph.
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For the point \((-3, -10)\): We have already calculated that at \( x = -3 \), \( y = -10 \). The point \((-3, -10)\) is on the graph.
Therefore, the point that does not belong to the graph of the function \( y = (x + 1)^3 - 2 \) is \((-3, 6)\).
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