To determine which point does not belong to the graph of the function \( y = (x + 1)^3 - 2 \), we need to evaluate the function for the given \( x \)-values and see if the corresponding \( y \)-values match.
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For the point \((-3, -10)\): \[ y = (-3 + 1)^3 - 2 = (-2)^3 - 2 = -8 - 2 = -10 \] Thus, the point \((-3, -10)\) is on the graph.
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For the point \((-3, 6)\): \[ y = (-3 + 1)^3 - 2 = (-2)^3 - 2 = -8 - 2 = -10 \] The \( y \)-value does not match; thus, the point \((-3, 6)\) is not on the graph.
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For the point \((0, -1)\): \[ y = (0 + 1)^3 - 2 = (1)^3 - 2 = 1 - 2 = -1 \] Thus, the point \((0, -1)\) is on the graph.
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For the point \((-2, -3)\): \[ y = (-2 + 1)^3 - 2 = (-1)^3 - 2 = -1 - 2 = -3 \] Thus, the point \((-2, -3)\) is on the graph.
From the evaluation, we find that:
- Points on the graph: \((-3, -10)\), \((0, -1)\), and \((-2, -3)\).
- Point not on the graph: \((-3, 6)\).
Therefore, the point that does not belong to the graph of the function is \((-3, 6)\).
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