The equation is y = 3x^2 - 4.
To check if an ordered pair (x, y) is part of the solution set for the equation, we substitute the values of x and y into the equation and see if it holds true.
Let's check each option:
Option #1: (-2, -8)
y = 3(-2)^2 - 4 = 12 - 4 = 8
The equation is not satisfied since y is not equal to -8.
Therefore, Option #1 is not part of the solution set.
Option #2: (2, 8)
y = 3(2)^2 - 4 = 12 - 4 = 8
The equation is satisfied since y = 8.
Therefore, Option #2 is part of the solution set.
Option #3: (-4, 0)
y = 3(-4)^2 - 4 = 3(16) - 4 = 48 - 4 = 44
The equation is not satisfied since y is not equal to 0.
Therefore, Option #3 is not part of the solution set.
So, the ordered pair (2, 8) is the only one that is part of the solution set for the equation.
Which of the following ordered pairs is part of the solution set for the equation y=3x^2−4
?
Option #1: (−2,−8)
Option #2: (2,8)
Option #3: (−4,0)
(1 point)
1 answer
1 answer