To determine which ordered pair is a solution to the equation, we substitute the values of x and y in each pair into the equation and see if the equation holds true.
For option a. (4,1), we have:
3x - 2y = 10
3(4) - 2(1) = 12 - 2 = 10
10 = 10
For option b. (0,-3), we have:
3x - 2y = 10
3(0) - 2(-3) = 0 + 6 = 6
6 ≠ 10
For option c. (-3,2), we have:
3x - 2y = 10
3(-3) - 2(2) = -9 - 4 = -13
-13 ≠ 10
For option d. (2,-1), we have:
3x - 2y = 10
3(2) - 2(-1) = 6 + 2 = 8
8 ≠ 10
Therefore, the only ordered pair that is a solution to the equation 3x-2y=10 is option a. (4,1).
Which of the following ordered pairs is a solution to the equation 3x-2y=10?
a. (4,1)
b. (0,-3)
c. (-3,2)
d. (2,-1)
1 answer