The lines that are perpendicular to y = -one-halfx + 4 have a slope that is the negative reciprocal of -one-half, which is 2.
Therefore, the lines y = 2x and 2x + y = 1 are perpendicular to y = -one-halfx + 4.
Which of the following lines are perpendicular to the line y = –one-halfx + 4? (you may choose more than one answer)
(2 points)
Responses
2x – y = 1
2 x – y = 1
y = 2x
y = 2 x
2x + y = 1
2 x + y = 1
one-halfx – y = 2
Image with alt text: one-half x – y = 2
2x – y = 3
1 answer