To simplify the expression \((-10x^2 + 20x + 80)/(x + 2)\), we can use polynomial long division or synthetic division.
Let's perform polynomial long division:
-
Divide the leading term of the numerator \(-10x^2\) by the leading term of the denominator \(x\) to get \(-10x\).
-
Multiply \(-10x\) by the entire divisor \((x + 2)\):
\[ -10x(x + 2) = -10x^2 - 20x \]
-
Subtract this result from the original numerator:
\[ (-10x^2 + 20x + 80) - (-10x^2 - 20x) = 20x + 20x + 80 = 40x + 80 \]
-
Now, divide the leading term of the new polynomial \(40x + 80\) by the leading term of the denominator \(x\):
\[ \frac{40x}{x} = 40 \]
-
Multiply the entire divisor by \(40\):
\[ 40(x + 2) = 40x + 80 \]
-
Subtract this from the remaining polynomial:
\[ (40x + 80) - (40x + 80) = 0 \]
The polynomial long division gives us:
\[ -10x + 40 \]
Since there is no remainder, the simplified form of \((-10x^2 + 20x + 80)/(x + 2)\) is:
\[ \boxed{-10x + 40} \]