I am trying to make sense of this. Perhaps you mean:
Which of the following is the same as the restricted-domain functionπ(π₯)=πππ‘(π₯),0β€π₯<2
(A) π(π₯)={0 ππ 0β€π₯<1 , 1 ππ π₯=1 , 2 ππ 1<π₯<2
(B) π(π₯)={0 ππ π₯=0 , 1 ππ 0<π₯β€1 , 2 ππ 1<π₯<2
(C) π(π₯)={0 ππ 0β€π₯<1 , 1 ππ 1β€π₯<2
(D) π(π₯)={0 ππ 0β€π₯<1 , 2 ππ 1β€π₯<2
(E)π(π₯)={π₯ ππ 0β€π₯<1 , 1+π₯ ππ 1β€π₯<2
0 is 0 , It can round down to zero if between 0 and 1
1 is 1, it can round down to 1 between 1 and 2
looks like C
Which of the following is the same as the restricted-domain functionπ(π₯)=πππ‘(π₯),0β€π₯<2
(A) π(π₯)={0ππ0β€π₯<11πππ₯=12ππ1<π₯<2
(B) π(π₯)={0πππ₯=01ππ0<π₯β€12ππ1<π₯<2
(C) π(π₯)={0ππ0β€π₯<11ππ1β€π₯<2
(D) π(π₯)={0ππ0β€π₯<12ππ1β€π₯<2
(E)π(π₯)={π₯ππ0β€π₯<11+π₯ππ1β€π₯<2
1 answer