To find the range of the inverse function \( f^{-1}(x) \) given \( f(x) = \log(x) + 3 \), we first determine the range of \( f(x) \).
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Function Analysis: The function \( f(x) = \log(x) + 3 \) is defined for \( x > 0 \) (since the logarithm function is only defined for positive values).
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Behavior of \( \log(x) \): The logarithm function \( \log(x) \) approaches negative infinity as \( x \) approaches 0 and increases without bound as \( x \) increases. Therefore:
- As \( x \to 0^+ \), \( \log(x) \to -\infty \).
- As \( x \to +\infty \), \( \log(x) \to +\infty \).
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Finding the Range of \( f(x) \): Adding 3 to \( \log(x) \) shifts the entire graph up by 3. Thus:
- As \( x \to 0^+ \), \( \log(x) + 3 \to -\infty + 3 = -\infty \).
- As \( x \to +\infty \), \( \log(x) + 3 \to +\infty + 3 = +\infty \).
Consequently, the range of \( f(x) \) is: \[ (-\infty, +\infty) \]
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Range of the Inverse Function: The range of the inverse function \( f^{-1}(x) \) corresponds to the domain of \( f(x) \). Since \( f(x) \) is defined for \( x > 0 \), the domain of \( f(x) \) is \( (0, +\infty) \).
Therefore, the range of \( f^{-1}(x) \) is: \[ (0, +\infty) \]
Based on the options given, the correct response is: (0,â).