Asked by Anonymous
Which of the following is the general solution of the differential equation dy dx equals the quotient of 8 times x and y?
Answers
Answered by
Damon
do you mean product of x and y?
dy/dx = 8 x y
or do you mean
dy/dx = 8 x / y
or what ?
if the latter then
y dy = 8 x dx
y^2/2 = 8 x^2/2 + C
y^2 - 8 x^2 = constant
dy/dx = 8 x y
or do you mean
dy/dx = 8 x / y
or what ?
if the latter then
y dy = 8 x dx
y^2/2 = 8 x^2/2 + C
y^2 - 8 x^2 = constant
Answered by
Anonymous
y'=8x/y
separation of variables...
y dy = 8x dx
1/2 y^2 + C=8/2x^2 + K
looks to me the general solution is
y^2=8 x^2 + K
check:
2ydy=16x dx
dy/dx=8x/y
separation of variables...
y dy = 8x dx
1/2 y^2 + C=8/2x^2 + K
looks to me the general solution is
y^2=8 x^2 + K
check:
2ydy=16x dx
dy/dx=8x/y
Answered by
Damon
We agree, if that is indeed the question :)
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