The line parallel to y = (5/4)x-1 that passes through the point (0,6) has the same slope as the given line, which is (5/4).
Using the point-slope form of a linear equation, y - y1 = m(x - x1), we can substitute the values into the equation to find the equation of the line:
y - 6 = (5/4)(x - 0)
y - 6 = (5/4)x
Now, we add 6 to both sides of the equation to isolate y:
y = (5/4)x + 6
Therefore, the equation of the line parallel to y = (5/4)x-1 that passes through the point (0,6) is y = (5/4)x + 6.
Which of the following is the equation of the line parallel to y= 5 4 x−1 that passes through the point (0,6) y= 5 4 x+5 y=− 4 5 x+6 y=− 4 5 x+5 y= 5 4 x+6
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